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If the equation of transverse wave is $Y = 2 \sin (kx - 2 t),$ then the maximum particle velocity is

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4 units

2 units

6 units

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detailed solution

Correct option is A

Maximum particle velocity =aω=2×2=4 units.

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If the equation of transverse wave is Y=2sin(kx−2t), then the maximum particle velocity is

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Ready to Test Your Skills?

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If the equation of transverse wave is $Y = 2 \sin (kx - 2 t),$ then the maximum particle velocity is