Questions
If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be
a
4%
b
6%
c
8%
d
2%
detailed solution
Correct option is B
Volume of a sphere = 43π (radius)3or V = 43πR3Taking logarithm on both sides, we havelog V = log 43π+ 3 log RDifferentiating we get ∆VV = 0+ 3∆RRAccordingly, ∆RR = 2%Thus, ∆VV = 3×2% = 6%Talk to our academic expert!
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A physical quantity P is given by . The quantity which brings in the maximum percentage error in P is
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