Questions
If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be
a
8%
b
2%
c
4%
d
6%
detailed solution
Correct option is D
V=43πR3;lnV=ln43π+lnR3Differentiating,dVV=3dRRError in the determination of the volume= 3 × 2% = 6%Talk to our academic expert!
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A physical quantity P is given by . The quantity which brings in the maximum percentage error in P is
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