Questions
If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be
detailed solution
Correct option is D
V=43πR3;lnV=ln43π+lnR3Differentiating,dVV=3dRRError in the determination of the volume= 3 × 2% = 6%Similar Questions
A physical quantity A is related to four observable a, b, c and d as . The percentage errors of measurement in a, b, c and d are 1 %, 3 %, 2 % and 2 % respectively. What is the percentage error in the quantity A ?
Want to Improve your productivity
talk to our academic experts now !!
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests