First slide

Accuracy; precision of instruments and errors in measurements

Question

If error in measurement of radius of a sphere is $1 %$ , what will be the error in measurement of volume?

Moderate

A

1%
B

$\frac{1}{3} %$
C

3%
D

None of these

Solution

$V = \frac{4}{3} π R^{3}$
$(% error in V) = 3 (% error in R)$
=3(1)=3%

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