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Q.

If error in measuring the length of a wire is 2 % and error in measuring its radius is 1 %, find the maximum possible error in its resistance

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a

4 %

b

2 %

c

2.5 %

d

3 %

answer is A.

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Detailed Solution

R=ρ.lπr2⇒R∝lr-2∴∆RRmax×100 %=∆ll × 100 %+2.∆rr × 100 %                                 =2 %+2 x 1 %=4 %
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