If escape velocity on earth surface is 11.1 kmh-1 then find the escape velocity on moon surface. If mass of moon is 181 times of mass of earth and radius of moon is 14 times radius of earth.

Given, escape velocity on the surface of earth, ve=11.1 km/hi.e.,     ve=2gRewhere, Re is radius of earth.As,     ve=2GMeRe                          ∵g=GMeRe2where, Me is mass of earth.Mass of moon,   Mm=Me81Radius of moon,  Rm=Re4∴  Escape velocity on the surface of moonvm=2GMmRm=2GMe81Re4=229GMeRe=292GMeRe=29ve=29×11.1=2.46 km h-1