If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is

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10.2 eV

0 eV

3.4 eV

6.8 eV

answer is C.

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Detailed Solution

Energy of n=2 orbit is E2=-13.6n2=-13.642=-3.4eVSo, Ionization energy will be +3.4eV

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