First slide

Bohr's atom model

Question

If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is

Easy

A

10.2 eV
B

0 eV
C

3.4 eV
D

6.8 eV

Solution

Energy of n=2 orbit is $E_{2} = - \frac{13.6}{n^{2}} = - \frac{13.6}{4^{2}} = - 3.4 e V$
So, Ionization energy will be +3.4eV

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