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If $2 f_{c}$ and $3 f_{m}$ are the frequencies of carrier wave and signal, then the bandwidth is

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6fm

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Correct option is B

LSB =2fc−3fm USB=2fc+3fm So, B.W = USB – LSB =2fc+3fm−2fc−3fm=6fm

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If 2fc and 3fm are the frequencies of carrier wave and signal, then the bandwidth is

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If $2 f_{c}$ and $3 f_{m}$ are the frequencies of carrier wave and signal, then the bandwidth is