First slide
Power
Question

If F=(60i^+15j^3k^)N and v=(2i^4j^+5k^)m/s, then instantaneous power is : 

Easy
Solution

P=  F.v=(60i^+15j^3k^).(2i^4j^+5k^)
= 60 (2) + 15 (-4) + (-3) (5)= 45 w

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