If $\overrightarrow{\mathrm{F}}=2\widehat{\mathrm{i}}-3\widehat{\mathrm{j}}\mathrm{N}$ and $\overrightarrow{\mathrm{r}}=3\widehat{\mathrm{i}}+2\widehat{\mathrm{j}}\mathrm{m}$ then torque $\overrightarrow{\mathrm{\tau }}$ is

• A

  $12\widehat{\mathrm{k}}$

• B

  $13\widehat{\mathrm{k}}$

• C

  $-12\widehat{\mathrm{k}}$

• D

  $-13\widehat{\mathrm{k}}$