If F $$=$$ $$vCln(xb)$$, then

Correct option is 2x denote distance, the dimensions of b are [L-1]

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$If F = \frac{v}{Cln (xb)}, then$

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F and v denote force and velocity, the dimensions of C are [MT]

x denote distance, the dimensions of b are [L-1]

the dimensions of vCcan never be same as F

the dimensions of x must be same as vcb

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detailed solution

Correct option is B

Logarithm has no dimensions.[xb] = [M0L0T0] ⇒[b] = [L-1]Hence, option (b) is correct

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If F = vCln(xb), then

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$If F = \frac{v}{Cln (xb)}, then$