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If in figure below R=200Ω and on connecting a 3 volt battery in the circuit, the barrier potential developed in diode is 0.5 volt, then the value of current in the circuit is

a
5.2mA
b
8.25 mA
c
12.5 mA
d
15.5 mA

detailed solution

Correct option is C

We know that V=E−IR or IR=E−V​⇒200I=3−0.5=2.5 or I=2.5200=12.5 mA

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