Questions
If force F, length L and time T be considered fundamental units of mass will be
a
[FLT−2]
b
[FL−2T−1]
c
[FL−1T2]
d
[F2LT−2]
detailed solution
Correct option is C
Let [M]∝[FaLbTc]So, using dimensions, we have[M1L0T0]=K[MLT−2]a[L]b[T]c=K[MaLa+bT−2a+b]We have, a =1, a = b = 0 and k =1 ∴ b=−1and −2a+c=0⇒c=2So unit of mass is [FL−1T2]Talk to our academic expert!
Similar Questions
The quantities A and B are related by the relation A/B = m, where m is the linear mass density and A is the force, the dimensions of B will be
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