If force (F), velocity (V) and time (T) are taken as the fundamental units, then the dimensions of mass are

Let m = FxVyTzBy substituting the following dimensions.[F] = [MLT-2], [V] = [LT-1], [T] = [T][M1L0T0] = [MLT-2]x[LT-1]y[T]z⇒ [M1L0T0] = [MxLx+yT-2x-y+z]x =1x+y = 0   ⇒y = -1-2x-y+z = 0  ⇒-2×1-(-1)+z = 0 ⇒ z = 1Hence [M] = FV-1T