If force F, velocity $v$ and time T are taken as fundamental units. The dimension of force in the dimensional formula of pressure is________________

$\left[F\right]=\left[ML{T}^{-2}\right]$

$\Rightarrow \left[v\right]=\left[L{T}^{-1}\right]$

$\begin{array}{l}\therefore \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\left[L\right]=\left[vT\right]\\ \therefore \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\left[M\right]=\frac{\left[F\right]}{\left[L{T}^{-2}\right]}=\frac{\left[F\right]}{\left[vT\right]\times \left[T^{-2}\right]}=\left[F{v}^{-1}T\right]\\ \therefore \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\text{Pressure }=\left[M{L}^{-1}{T}^{-2}\right]\\ =\left[F{v}^{-1}T\right]{\left[vT\right]}^{-1}\left[T^{-2}\right]=\left[F{v}^{-2}{T}^{-2}\right]\end{array}$

Thus, in the dimensional formula of pressure, the dimension of force is 1.