First slide

Second law

Question

If force on a rocket having exhaust velocity of 300 m/sec is 210 N, then rate of combustion of the fuel is

Moderate

A

$0 .7 kg / s$
B

$1 .4 kg / s$
C

$0 .07 kg / s$
D

$10 .7 kg / s$

Solution

$F = u (\frac{dm}{dt}) \Rightarrow \frac{dm}{dt} = \frac{F}{u} = \frac{210}{300} = 0 .7 kg / s .$

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