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Questions  

If four bar magnets of moments M,2M,3M and 4M  arranged to form a square with unlike poles at each corner, then its  new magnetic moment is 

a
5M
b
5M
c
22M
d
5−5M

detailed solution

Correct option is C

M→1=3M (+i^)M→2=4M (-j^)M→3=M (-i^)M→4=2M (+j^)Hence, M→net=3M (+i^)+4M (-j^)+M (-i^)+2M (+j^) = 2Mi^-2Mj^⇒M→net=22M

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