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Q.

If four bar magnets of moments M,2M,3M and 4M  arranged to form a square with unlike poles at each corner, then its  new magnetic moment is

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a

5M

b

5M

c

22M

d

5−5M

answer is C.

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Detailed Solution

M→1=3M (+i^)M→2=4M (-j^)M→3=M (-i^)M→4=2M (+j^)Hence, M→net=3M (+i^)+4M (-j^)+M (-i^)+2M (+j^) = 2Mi^-2Mj^⇒M→net=22M
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If four bar magnets of moments M,2M,3M and 4M  arranged to form a square with unlike poles at each corner, then its  new magnetic moment is