if $$f(x)$$ $$=$$ $$cos3(x2)$$ then find f '(x)

Correct option is 1–6xcos2 (x2)sin(x2)

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if f(x) = cos³(x²) then find f '(x)

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–6xcos2 (x2)sin(x2)

6xcos2 (x2)sin(x2)

3xcos (x2)sin(2x2)

–3cos (x4)sin(2x2)

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detailed solution

Correct option is A

f'x=3cos2x2×-sinx2×2x

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if f(x) = cos3(x2) then find f '(x)

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if f(x) = cos³(x²) then find f '(x)