If g is the acceleration due to gravity on the earth's surface, the gain in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is
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a
2mgR
b
mg(R/2)
c
mg(R/4)
d
MgR
answer is B.
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Detailed Solution
The gravitational potential energy of the body on earth's surfaceUR=GMmRAt a height h from the earth's surfaceUR+h=−GMm(R+h)=−GMm2R (∵h=R)Therefore, gain in potential energy=UR+h−U=−GMm2R−−GMmR=GMm2R=gmR22R=12mgR