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Questions  

If g is acceleration due to gravity on the surface of the earth ,having radius R , the height at which the acceleration due to gravity reduces tog2 is 

a
R/2
b
2R
c
R/2
d
2-1R

detailed solution

Correct option is D

gh=gRR+h2 ⇒g2=gRR+h2 ∵ gh=g2 ⇒12=RR+h2 ⇒12=RR+h ⇒R+h=2R ⇒h=2-1R

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