First slide

Acceleration due to gravity and its variation

Question

If g is same at a height h and at a depth d, then

Moderate

A

R = 2d
B

d = 2h
C

h = d
D

none

Solution

$\begin{array}{l} g^{'} = g [1 - \frac{2 h}{R}] = g [1 - \frac{d}{R}] \\ \frac{2 h}{R} = \frac{d}{R} \Rightarrow d = 2 h \end{array}$

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