If a glass prism is dipped in water, its dispersive power
increases
decreases
does not change
may increase or decrease depending on whether the angle of the prism is less than or greater then 60o
Dispersive power of a prism ω=μV−μRμy−1 (when prism is in air)
When outside medium is changed to water, new dispersive power is given by ωnew=μVμw−μRμwμyμw−1 = μV − μRμy − μw Hence dispersive power increases when prism is dipped in water.