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Q.

If H1 and H2 be the greatest heights of a projectile in two paths for a given value of range, then the horizontal range of projectile is given by

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a

H1+H22

b

H1+H24

c

4H1H2

d

4H1+H2

answer is C.

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Detailed Solution

θ1+θ2=90∘H1=u2sin2⁡θ12g&H2=u2sin⁡90∘−θ12gH1H2=R216∵R=u2sin2θ1g⇒R=4H1H2
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