First slide

Radio activity

Question

If half-life of a substance is 3.8 days and its quantity is 10.38 gm. Then substance quantity remaining left after 19 days will be

Moderate

A

0.151 gm
B

0.32 gm
C

1.51 gm
D

0.16 gm

Solution

Number of half-lives $n = \frac{19}{3.8} = 5; Now \frac{N}{N_{0}} = {(\frac{1}{2})}^{n}$
$\Rightarrow \frac{N}{10.38} = {(\frac{1}{2})}^{5} \Rightarrow N = 10.38 x {(\frac{1}{2})}^{5} = 0.32 gm$

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