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If half-life of a substance is 3.8 days and its quantity is 10.38 gm. Then substance quantity remaining left after 19 days will be

a
0.151 gm
b
0.32 gm
c
1.51 gm
d
0.16 gm

detailed solution

Correct option is B

Number of half-lives n=193.8=5; Now NN0=12n⇒N10.38=(12)5⇒N=10.38 x (12)5=0.32 gm

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