First slide

First law of thermodynamics

Question

If the heat of 110 J is added to a gaseous system and change in internal energy is 40 J, then the amount of external work done is :

Easy

A

140 J
B

70 J
C

110 J
D

150 J

Solution

$W = Q - ΔU = (100 - 40) J = 70 J$

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