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Questions  

If i^ , j^  and k^  are unit vectors along x, y and z-axes respectively, the angle θ  between the vector i^+j^+k^  and vector i^  is given by

a
θ=cos−1(13)
b
θ=sin−1(13)
c
θ=cos−1(32)
d
θ=sin−1(32)

detailed solution

Correct option is A

cosθ=(i^+j^+k^). i^(12+12+12)12×12=i^.i^+j^.i^+k.i^(1+1+1)12×1=1+0+03=13

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