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Q.

If i^ , j^  and k^  are unit vectors along x, y and z-axes respectively, the angle θ  between the vector i^+j^+k^  and vector i^  is given by

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a

θ=cos−1(13)

b

θ=sin−1(13)

c

θ=cos−1(32)

d

θ=sin−1(32)

answer is A.

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Detailed Solution

cosθ=(i^+j^+k^). i^(12+12+12)12×12=i^.i^+j^.i^+k.i^(1+1+1)12×1=1+0+03=13
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