If $\overrightarrow{\mathrm{A}}=3\mathrm{i}+\mathrm{j}+2\mathrm{k}$ and  $\overrightarrow{\mathrm{B}}=2\mathrm{i}-2\mathrm{j}+4\mathrm{k}$ is the angle between the two vectors, then $\sin \mathrm{\theta }$ is equal to

• A

  $\frac{2}{3}$

• B

  $\frac{2}{\sqrt{3}}$

• C

  $\frac{2}{\sqrt{7}}$

• D

  $\frac{2}{\sqrt{13}}$