Download the app

Questions  

If A=3i^+j^+2k^  and  B=2i^2j^+4k^  then  value  of  |A×B|  will  be

a
82
b
83
c
85
d
58

detailed solution

Correct option is B

A→ ×B→ = i^j^k^3122−24= 1×4−2×−2i^ -2×2−4×3j^ +(3×−2−1×2)k^= 8i^ −8j^ −8k^∴Magnitude of A→ ×B→ = |A→ ×B→|= 82+(−8)2+(−8)2 = 83

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Two vectors 2i^+3j^k^  and 4i^6j^+λk^ are parallel to each other then value of λ will be


phone icon
whats app icon