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Q.

If A→ = 3i^+j^+2k^  and  B→ = 2i^−2j^+4k^  then  value  of  |A→ ×B→|  will  be

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a

82

b

83

c

85

d

58

answer is B.

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Detailed Solution

A→ ×B→ = i^j^k^3122−24= 1×4−2×−2i^ -2×2−4×3j^ +(3×−2−1×2)k^= 8i^ −8j^ −8k^∴Magnitude of A→ ×B→ = |A→ ×B→|= 82+(−8)2+(−8)2 = 83
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