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If $\vec{A} = - 2 \hat{i} + 3 \hat{j} - 4 \hat{k}$ and $\vec{B} = 3 \hat{i} - 4 \hat{j} + 5 \hat{k}$ , then $sinθ =$ is

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Correct option is A

sin⁡θ=|A→×B→||A→||B→|A→×B→=−i^−2j^−k^i.e., |A→×B→|=(1)2+(2)2+(1)2=6|A→|=(−2)2+(3)2+(−4)2=29|B→|=(3)2+(−4)2+(5)2=50∴sin⁡θ=629×50

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If A→=-2i^+3j^-4k^and B→=3i^-4j^+5k^, then sinθ= is

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If $\vec{A} = - 2 \hat{i} + 3 \hat{j} - 4 \hat{k}$ and $\vec{B} = 3 \hat{i} - 4 \hat{j} + 5 \hat{k}$ , then $sinθ =$ is