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If $\vec{A} = \hat{i} + 2 \hat{k} - \hat{k}, \vec{B} = - \hat{i} + \hat{j} - 2 \hat{k}$ then angle between $\vec{A}$ and $\vec{B}$ is

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π/2

π/3

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detailed solution

Correct option is D

A→=i^+2j^−k^;B→=i^+j^−2k^ A=|A→|=12+22(−1)2=6 B=|B→|=(−1)2+12(−2)2=6 A→.B→=(i^+2j^−k^).(−i^+j^−2k^) =−1+2+2=3 If θ is angle between A→ and B→ , then A→.B→=ABcosθ 3=66cosθ cosθ=36=12 or θ=π3

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If A→=i^+2k^−k^,B→=−i^+j^−2k^ then angle between A→ and B→ is

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If $\vec{A} = \hat{i} + 2 \hat{k} - \hat{k}, \vec{B} = - \hat{i} + \hat{j} - 2 \hat{k}$ then angle between $\vec{A}$ and $\vec{B}$ is