Questions
If I1 is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass and I2 is the moment of inertia of ring about an axis perpendicular to the plane of ring and passing through its centre formed by bending the rod, then
detailed solution
Correct option is C
length of the rod l=2πr r=l2πI1=ml212 and I2=mr2=ml2π2=ml24π2I1I2=4π212=π23Talk to our academic expert!
Similar Questions
The moment of inertia of a circular disc of radius 2 m and mass 2 kg, about an axis passing through its centre of mass is 2 kg – . Its moment of inertia about an axis parallel to this axis and passing through its edge (in Kg -) is
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