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Questions  

If i1=3 sin ωt and i2=4 cos ωtt,then i3 is

a
5 sinωt+530
b
5 sinωt+370
c
5 sinωt+450
d
5 sinωt+430

detailed solution

Correct option is A

i3=i1+i2=3 sin ωt+4 cosωt=3sinωt+4sinωt+900i30=i102+i202=32+42=5tanϕ=43⇒ϕ=530So  i3=i30 sinωt+ϕ=5 sinωt+530

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