If i1=3 sin ωt and i2=4 cos ωtt,then i3 is

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5 sinωt+530

5 sinωt+370

5 sinωt+450

5 sinωt+430

answer is A.

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Detailed Solution

i3=i1+i2=3 sin ωt+4 cosωt=3sinωt+4sinωt+900i30=i102+i202=32+42=5tanϕ=43⇒ϕ=530So i3=i30 sinωt+ϕ=5 sinωt+530

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