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Potential energy
Question

If identical charges (-q) are placed at each corner of a cube of side b, then electric potential energy of charge ( +q) which is placed at centre of the cube will be

Easy
Solution

Length of the diagonal of a cube having each side b is 3b. So distance of centre of cube from each vertex is 3b2

Hence potential energy of the given system of charges is

U=8×14πε0·(-q)(q)3b/2=-4q23πε0b

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