If the intensity of the incident radio wave of $1watt{m}^{-2}$ is reflected by the surface the pressure exerted on the surface is $\_\_\_\_\_\_\_\_\times {10}^{-9}N/m^2$

Pressure exerted by reflected wave on the surface is  $P=\frac{2I}{C}$
Intensity of incident, radio wave is  $I=1watt{m}^{-2}$
Velocity of light ,  $C=3\times {10}^{8}m{s}^{-1}$
Pressure ,   $P=\frac{2\times 1}{3\times {10}^8} P=6.67\times {10}^{-9}N/m^2$