First slide

Intensity of

Question

If the intensity of sound is doubled, the intensity level will increase by

Moderate

A

1 dB
B

2dB
C

3dB
D

4dB

Solution

Here
$\frac{I_{2}}{I_{1}} = 2 or \frac{I_{2} / I_{0}}{I_{1} / I_{0}} = 2 10 \log_{10} (\frac{I_{2}}{I_{0}}) - 10 \log_{10} (\frac{I_{1}}{I_{0}}) = 10 \log_{10} 2 or {dB}_{2} - {dB}_{1} = 3 (∵ \log_{0} 2 ≅ 0 \cdot 3)$

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