First slide
Motion in a plane
Question

If \large \vec A=2\hat i-3\hat j+4\hat k its components in yz plane and zx plane are respectively

Moderate
Solution

\large \overline A = 2\widehat i - 3\widehat j + 4\widehat k = {A_x}\widehat i + {A_y}\widehat j + {A_z}\widehat k
→ In yz plane = \large \sqrt {A_y^2 + A_z^2} = \sqrt {{{( - 3)}^2} + {4^2}}\large = \sqrt {9 + 16} = 5units
→ In zx plane = \large \sqrt {A_z^2 + A_x^2} = \sqrt {16 + 4} = 2\sqrt 5 units
\large \therefore 5 and 2√5

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