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If J is angular momentum and E is the Kinetic energy, then $J^{2} / E$ has the dimensions of

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Correct option is A

J2E=(mvr)212mv2=2mr2=I J2E has the dimensions of moment of inertia (I)

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If J is angular momentum and E is the Kinetic energy, then J2/E has the dimensions of

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If J is angular momentum and E is the Kinetic energy, then $J^{2} / E$ has the dimensions of