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If the $K_{α}$ radiation of Mo (Z = 42) has a wavelength of 0.71 $Å$ the wavelength of the corresponding radiation of Cu (Z = 29)

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1 Å

2 Å

1.52 Å

1.25 Å

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detailed solution

Correct option is C

Moseley's law For Kα , λ ∝ 1Z-12λ2λ1=Z1-12Z2-12 ⇒λ20.71=(42-1)2(29-1)2 ⇒λ2=1.522A˙

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If the Kα radiation of Mo (Z = 42) has a wavelength of 0.71 Å the wavelength of the corresponding radiation of Cu (Z = 29)

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If the $K_{α}$ radiation of Mo (Z = 42) has a wavelength of 0.71 $Å$ the wavelength of the corresponding radiation of Cu (Z = 29)