Question

If the kinetic energy of a body increases by 0.1%, the percent increase of its momentum will be (in %)

Moderate

Solution

$P = \sqrt{2 mE} ∴ P \propto \sqrt{E}$
Percentage increase in $P = \frac{1}{2}$ (percentage increase in E)
$= \frac{1}{2} (0 .1 %) = 0 .05 %$

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