If the kinetic energy of the moving particle is E, then the de-Broglie wavelength is

• A

  $\mathrm{\lambda }=\mathrm{h}\sqrt{2\mathrm{mE}}$

• B

  $\mathrm{\lambda }=\sqrt{\left(\frac{2\mathrm{mE}}{\mathrm{h}}\right)}$

• C

  $\mathrm{\lambda }=\frac{\mathrm{h}}{\sqrt{2\mathrm{mE}}}$

• D

  $\mathrm{\lambda }=\frac{\mathrm{hE}}{\sqrt{2\mathrm{mE}}}$