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Q.

If the kinetic energy of the moving particle is E, then the de-Broglie wavelength is

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a

λ=h2mE

b

λ=2mEh

c

λ=h2mE

d

λ=hE2mE

answer is C.

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Detailed Solution

λ=hmv E=12mv2  or  2mE=m2v2 or mv=2mE λ=h2mE
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