Download the app

Questions  

If the kinetic energy of the particle is increased to 16 times its previous vlaue, the percentage change in the de Broglie wavelength of the particle is 

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
25
b
75
c
60
d
50

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is

de Broglie wavelength, λ=h2mKwhere m is the mass and K is the kinetic energy of the particle. When kinetic energy of the particle is increased to 16 times, then its de Broglie wavelength becomes,λ'=h2m(16K)=14λ2mK=λ4             (Using (i))% change in the de Broglie wavelength =λ-λ'λ×100=1-λ'λ×100=1-14×100=75%

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?

ctaimg

Create Your Own Test
Your Topic, Your Difficulty, Your Pace


Similar Questions

An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to


phone icon
whats app icon