If L and R denote inductance and resistance respectively, then the dimensional formula of L/R is:
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a
M1L0T0Q−1
b
M0L0TQ0
c
M0L1T−1Q0
d
M−1LT0Q−1
answer is B.
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Detailed Solution
time constant DURING the growth of LR CIRCUIT IS τ=LRIn M(meter)-K(kilogram)-S(second)-Q(charge) system, SO LR will have the dimensions of time. Energy stored in inductor is U=12Li2Heat developed in resistor is, H=i2Rt; Equating both L=Rt or L/R= t. (or)Dimension of L=M1L2T0Q-2Dimension of R=M1L2T-1Q-2Dimension of L/R =M1L2T0Q-2M1L2T-1Q-2=M0L0TQ0