If the length of a cylinder is measured to be 4.28cm with an error of 0.01cm, the percentage error in the measured length is nearly.

length of cylinder measured is l=4.28cm error is Δl=0.01cm percentage error=Δll×100 substitute given values percentage error=0.014.28×100 percentage error=100428=0.23 percentage error in measured length =0.2%