If the length of the filament of a heater is reduced by 10%  by cutting its length, the power of the heater will be nearly, (if constant voltage is maintained across the heater)

Power of a heater is given as P=V2R⇒P∝1R      resistance of a wire is directly propotional to its length.⇒P2P1=R1R2=l1l2⇒P2=l1l2P1=l0.9lP1=1.11P1So, power will be  increased by 11%.