First slide

Applications of SHM

Question

If the length of a pendulum is made 9 times and mass of the bob is made 4 times then the value of time period becomes

Moderate

A

3T
B

3/2T
C

4T
D

2T

Solution

$T = 2 π \sqrt{\frac{l}{g}} \Rightarrow T \propto \sqrt{l}, \frac{T_{2}}{T_{1}} = \sqrt{\frac{l_{2}}{l_{1}}} = \sqrt{\frac{9 l_{1}}{l_{1}}} = 3$
Hence if l made 9 times T becomes 3 times.

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