First slide

Applications of SHM

Question

If the length of second's pendulum is decreased by 2%, how many seconds it will lose per day

Moderate

A

3927 sec
B

3727 sec
C

3427 sec
D

864 sec

Solution

$T \propto \sqrt{l}$ $\Rightarrow \frac{ΔT}{T} = \frac{1}{2} \frac{Δl}{l} = \frac{0 .02}{2} = 0 .01$ $\Rightarrow ΔT = 0 .01 T$
Loss of time per day $= 0 .01 \times 24 \times 60 \times 60 = 864 \sec$

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