If light of wavelength corresponding to maximum intensity emitted from a surface of hot body at temperature $$T1$$ is used to cause photoelectric emission from a metallic surface, then maximum kinetic energy of the emitted photo electron is $$6eV$$, which is $$3$$ times the work function of the metallic surface. If the light of wavelength of maximum intensity emitted from a surface of same body at temperature $$T2(T2=2T1)$$ is used, the maximum kinetic energy of photoelectrons emitted is (in$$ $$eV)

Question

If light of wavelength corresponding to maximum intensity emitted from a surface of hot body at temperature $$T1$$ is used to cause photoelectric emission from a metallic surface, then maximum kinetic energy of the emitted photo electron is $$6eV$$, which is $$3$$ times the work function of the metallic surface. If the light of wavelength of maximum intensity emitted from a surface of same body at temperature $$T2(T2=2T1)$$ is used, the maximum kinetic energy of photoelectrons emitted is (in$$ $$eV)

Infinity Learn · Accepted Answer

Case $$1$$ : hcλ$$1=2eV+6eV$$⇒λ$$1=hc8eVCase$$ $$2$$ : hcλ$$2=2eV+KEmax$$⇒ λ$$2$$ λ$$1=T1T2=T2T=12$$ Wien's Displacement Law , λm∝$$1T$$    λ$$2=$$λ$$12$$⇒λ$$2=hc16eV$$∴$$16eV=2eV+KEmax$$⇒$$KEmax=14eV$$

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