If the linear momentum is increased by 50%, the kinetic energy will increase by (in %)

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answer is 125.

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Detailed Solution

Let P1=P , P2=P1+50% of P1=P1+P12=3P12E∝P2 ⇒E2E1=P2P12=3P1/2P12=94⇒E2=2.25E=E1+1.25E1∴E2=E1+125% of E1 i.e. kinetic energy will increase by 125%.

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