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Q.

If a load of 9 kg is suspended on a wire, the increase in length is 4.5 mm. The force constant of the wire is

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a

0.49×104 N/m

b

1.96×104 N/m

c

4.9×104 N/m

d

0.196×104 N/m

answer is B.

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Detailed Solution

F=Kx⇒K=Fx=9×9.84.5×10−3=1.96×104N/m
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