First slide

Concept of potential energy

Question

If a long spring is stretched by 0.02 m, its potential energy is U. If the spring is stretched by 0.1 m, then its potential energy will be nU. The value of n is

Moderate

Solution

$U \propto x^{2} \Rightarrow \frac{U_{2}}{U_{1}} = {(\frac{x_{2}}{x_{1}})}^{2} = {(\frac{0 .1}{0 .02})}^{2} = 25 ∴ U_{2} = 25 U$

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