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Q.

If a long spring is stretched by 0.02 m, its potential energy is U. If the spring is stretched by 0.1 m, then its potential energy will be nU. The value of n is

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answer is 25.

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Detailed Solution

U∝x2⇒U2U1=x2x12=0.10.022=25      ∴U2=25U
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